How deep and wide do footings need to be? This is another question along the liens of “how long is a piece of string”. There are however some easy to understand principles which do answer the question of “how deep and wide do footings need to be”. Lets grab a coffee and take a closer look…

**How wide and deep a footing needs to be is dependant on a number of factors which include:**

**The load the footing is required to support****The soil conditions and how stiff or strong the founding material is****The footing type which has been selected****The strength grade of the materials used for constructing the footing****Whether the footing is located in a seismically sensitive region**

There are a number of different types of footings which Structural Engineers can chose from and each has its own application. Footings are required to support single storey houses, warehouse sheds, office towers large skyscrapers and more.

This article will use an isolated shallow pad footing as an example reference to answer the question “how deep and wide do footings need to be”.

## How Wide an Isolated Footing Needs to be

An isolated footing is rectangular or square in nature. It usually supports a single structural column. In some cases it can support more than one column however this arrangement is not as common. Here is a 3D view of an isolated footing supporting a single concrete column (sometimes also referred to as a pad footing, for a related article on pad footings take a look at THIS link)…

In terms of how deep and wide an isolated footing needs to be, we will break this question down and first look at how the width is determined (and also considering its a square, how the length is determined also).

There are a number of factors which influence how wide an isolated footing needs to be which includes:

- The allowable bearing capacity of the soil upon which it is founded on (to see how geotechnical engineers determine the bearing capacity of soil, take a look at THIS article)
- The applied vertical load on the column as well as any bending moment
- The aspect ratio of the column

We will look at each factor in isolation…

### How Soil Bearing Capacity Determines how Wide an Isolated Footing Needs to be

Lets take a look at a very simple square column which is propose to be supported by a square shaped isolated footing. Here is a plan view of this arrangement…

Now lets place some hypothetical loads on our column which this footing needs to support and also assume a bearing capacity for our soil:

**Column Load =**1,500 kN (or 1.5 tonne or 380,000 lbs)**Soil Bearing Capacity =**500 kPa (or 72.5 psi)

The soil bearing capacity is a representation of how much pressure (a force divided over a given area) the soil can support before it fails. Therefore the footings width needs to be sized accordingly to ensure that the soil is not over-stressed.

kPa, or Kilopascal is also expressed as kN/m^{2} so dividing our column load by the soil bearing capacity gives us how large the footing needs to be in square metres.

**1,500 / 500 = 3 m ^{2}**

Now we know that our footing needs to be at least 3 m^{2} in order to adequately spread our 1,500kN of load over a large enough area of soil to ensure that the soil does not fail. Therefore a width of 1.75 m should be enough to provide this area (roughly the square root of 3). Lets verify this…

**1.75 x 1.75 = 3.06 m ^{2}**

If we placed this same footing on a new site where the soil is not quite as strong (say half as strong therefore 250kPa capacity), then our footing will need to double in area given the same load. Equally, if the soil was twice as strong on another site (1,000kPa capacity) then the 3m^{2} footing can be halved in size.

## How Applied Load Effects how Wide an Isolated Footing Needs to be

We can now explore how the applied load effects the width of an isolated footing. Lets say that we wish to double our original load (increase from 1,500kN to 3,000kN), this means that the footing area will also need to double.

Equally, if we were to halve this load (decrease from 1,500kN to 750kN), the footing area too may be halved.

But what now if we were to apply an overturning moment to the column which this footing supports? Lets first take a look at the stress distribution under the original 3m^{2} footing under the vertical load only…

As we can see everything works fine and our soil stress equals that of the soil bearing capacity (500kPa). Lets now apply an overturning moment at the same time to this column by pushing it from left to right. We will assume this is a wind load case so it may not always be present but will be applied from time to time on the column based on weather conditions…

To determine the stress introduce to the soil due to this overturning moment, we need to first determine the footings section modulus, which is determined by…

Therefore our section modulus is (1.75 x 1.75^{2})/6 = 0.89m^{3}

The actual resultant stress is then the overturning moment divided by the section modulus which gives us…

**200 / 0.89 = 224MPa**

We now have two forces acting upon the footing and therefore two stress distributions imposed on to the soil…

Adding these two stress distributions together gives us the net pressure that the soil needs to support…

We can see that the introduction of the overturning moment has reduced the soil stress on the left hand side of the footing. However it has also significantly increased the stress on the right hand side. The stress on the right hand size of the footing is now exceeding the soils capacity of 500kPa. This means that soil failure will occur. We will need to increase the size of the footing to prevent this from occurring.

To resize this isolated footing will require a little trial and error. By increasing its length we are reducing the stress caused by the vertical load (by increasing its area) as well as the overturning moment (by increasing its section modulus). A few trial runs shows that the length needs to be increased to circa 2.4m to reduce the soil stress back down below 500kPa. Lets verify this…

Area now becomes 2.4 x 1.75 = 4.2 m^{2}

Section Modulus Now becomes (1.75 x 2.4^{2})/6 = 1.68m^{3}

To determine the peak stress we simply apply the folowing equation…

Plugging everythign into this equation we can now determien what our new peak stress is with this larger footing…

**(1,500 / 4.2) + (200 / 1.68) = 490 kPa**

We are now slightly under the allowable soil bearing capacity of 490kPa which now means our design is adequate. This is how you solve the answer of “how wide do footings need to be” with respect to isolated pads. But what about its depth? Lets look at that next…

## How Deep an Isolated Footing Needs to be.

The depth of a footing can mean one of two things…

- What the founding depth of the footing is (at what depth the base of the footing contacts the support soil)
- How deep or thick the actual footing is itself (its structural depth).

The founding depth of a footing is determined by the soil profile which it needs to sit upon. More often than not, support soil becomes stronger with larger founding depths. A Geotechnical Engineer performs a site investigation through core hole sampling of the soil. From this study, the required founding depth can be determined.

The Structural depth of the footing requires calculation from the Structural Engineer.

The pad footing can fail in two forms of shear, punching shear, and one-way shear. It is best practice to size the depth of the footing to ensure that the concrete has sufficient capacity to support the shear load without the assistance of additional shear reinforcement. This can be achieved through modifying the footings thickness (or depth). Therefore the depth of the footing is dependant upon the applied load of the column.

## Final Thoughts

This article has been a very high level look at the sizing of footings. For a more thorough example including a step-by-step process on how to actually calculate the depth and width of an isolated footing, take a look at THIS article. There I also provide a design spreadsheet which you can have a play around with for isolated footing design in accordance with the Australian Concrete Design Code AS3600.

Feature Image Source: S3DA Design

Going back to your article about top reo in pad footings. If we didn’t have any compression loads, would the pad footing subject to -224kPa require top reo?

Hi there eeargabriel, thanks for your question and contribution to this post. Without compression loads on this footing (and only the overturning component), it would most likely require top reinforcement. It should be noted that a “reversal case” should be checked to make absolutely certain if tension is present in the top layer of the footing.

This would consist of a minimum vertical load (say just the self-weight only) and an additional reduction factor (in the case of Australian codes a reduction of 0.9 is applied).

Further to this, if you are relying on fixity at the base of your column and moment transfer between column and pad, the earthquake condition should also definitely be checked and may be the governing factor of the design to determine your top reinforcement requirements of the pad footing.